x+20+x+20+x^2=180

Solution for x+20+x+20+x^2=180 equation:

X+20+X+20+X^2=180

We move all terms to the left:

X+20+X+20+X^2-(180)=0

We add all the numbers together, and all the variables

X^2+2X-140=0

a = 1; b = 2; c = -140;
Δ = b2-4ac
Δ = 22-4·1·(-140)
Δ = 564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{564}=\sqrt{4*141}=\sqrt{4}*\sqrt{141}=2\sqrt{141}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{141}}{2*1}=\frac{-2-2\sqrt{141}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{141}}{2*1}=\frac{-2+2\sqrt{141}}{2}
$